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29:62 General Astronomy
First Hour Exam
February 14, 1997

All problems are worth 10 points. Write legibly, preferably in pen. Good luck and no whining.

(1) A star has a surface temperature of 10000K. Draw an accurate plot of its continuum spectrum, with a correct labeling (with numbers) of the wavelength axis.

Answer: The plot should be of radiative flux density versus wavelength. The spectrum should be a continuum one, and show a maximum at a wavelength given by tex2html_wrap_inline100 . Plugging in the numbers, we have tex2html_wrap_inline102 meters, or 288 nanometers.

(2) Describe how we can determine the temperature of the solar corona. The more numerical information you can furnish, the better.

Answer: The best indicator is of spectral lines from highly ionized atoms. Examples would be iron X and Ni XV. These ions have ionization potentials of the order of 300 to 400 electron volts. There is no way electrons could collisionally ionize atoms to such a state unless the gas has temperatures of order tex2html_wrap_inline104 electron volts, or tex2html_wrap_inline106

(3) What is the typical speed of an electron in the solar wind? The solar wind has a temperature of tex2html_wrap_inline108 K. The mass of an electron is tex2html_wrap_inline110 kg.

Answer: We use the relationship between the mean kinetic energy and the temperature, tex2html_wrap_inline112 . Rearranging, the root mean squared speed is tex2html_wrap_inline114 meters/sec.

(4) See the energy level diagram of a hypothetical atom in the Figure 1. In an experiment, an electron beam (all electrons have the same energy) is passed through the gas, collisionally ionizing the atoms. They recombine, and emission lines are produced as a result. 1 electron volt (eV) = tex2html_wrap_inline116 Joules.
(a) What must the energy of the ionizing electrons be?
(b) Which of the radiative transitions is in the ultraviolet?
(c) What is the wavelength of this transition or transitions?

Answer: (a) The energy of the electrons must be at least 9 electron volts, since this is the ionization potential of the atom. (b) Transitions in the ultraviolet have wavelengths less than 400 nanometers = tex2html_wrap_inline118 meters. The energy of a photon is given by tex2html_wrap_inline120 = tex2html_wrap_inline122 Joules or 3.10 electron volts. Looking at the energy level diagram in Figure 1 we see that the following transitions have this much energy: tex2html_wrap_inline124 , and tex2html_wrap_inline126 . (c) The wavelengths of these transitions are 250nm, 207nm, 177, and 155 nm, respectively.

(5) A star is known to have an absolute magnitude of -2. It is observed with an apparent magnitude of 4. What is the distance to this star?

Answer: The distance modulus is m-M = 6 magnitudes. Using the relationship between distance modulus and distance, tex2html_wrap_inline130 where d is the distance in parsecs, we have tex2html_wrap_inline134 parsecs.

(6) Assume an atom has a first ionization potential of 1.0 electron volts. For what class of stars would you expect to see spectral lines of the neutral atom? Describe your reasoning and calculations.

Answer: If the first ionization potential is 1.0 electron volts, the mean energy per particle should be of the order of 0.5 electron volts to get a significant amount of ionization. Thus tex2html_wrap_inline136 J, or tex2html_wrap_inline138 K. This is lower than the temperature of the sun, and is characteristic of a spectral class K or M star. Mathematical Formulae

Note: All units MKS unless otherwise indicated.
Wien's Law: Wavelength at which a blackbody radiator is brightest

equation48

where tex2html_wrap_inline140 (Planck's Constant), tex2html_wrap_inline142 (speed of light), tex2html_wrap_inline144 .
Kinetic Energy of Thermal Motion:

equation58

where m is the mass of the particle (electron, atom, ion, molecule) and v is its speed. Relation between Flux and Magnitude:
tex2html_wrap_inline150 is the flux (Watts/m tex2html_wrap_inline152 ) from object 1, tex2html_wrap_inline154 is that from object 2, tex2html_wrap_inline156 is the magnitude of object 1, and tex2html_wrap_inline158 is the magnitude of object 2. Then,

equation72

equation78

Energy of a Photon: tex2html_wrap_inline160

equation86

equation88

where tex2html_wrap_inline162 is the wave frequency (units Hertz). Photon energy is often conveniently expressed in electron volts, 1 eV = tex2html_wrap_inline164 Joules.




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Steve Spangler
Tue Feb 18 15:06:10 CST 1997